1.

Two batteries of emf E_(1) and E_(2)(E_(2) gt E_(1)) and internal resistances r_(1) and r_(2) respectively are connected in parallel as shown in figure.

Answer»

Two batteries of emf E1 and Ei{E2 GT E1) and internal resistances r1 and r2 respectively are connected in parallel as shown in figure.
The equivalent emf Eeq is smaller than E
Two batteries of emf E1 and Ei{E2 gt E1) and internal resistances r1 and r2 respectively are connected in parallel as shown in figure.

Solution :As the metwer bridge is balanced.
`therefore (R)/(S)=(l_(1))/((100-l_(1)))`
`or R=(Sl_(1))/((100-l_(1)))=((100Omega)(2.9cm))/((100-2.9)CM)approx3Omega`
The accuracy of MEASURING R can be improved if S and R are of the same ORDER, i.e. S should be changed to `3OMEGA`.


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