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Two beaker A and B contain water at different temperatures .When 1 liter of water from beaker A is mixed with 2 litre of water from beaker B the equilibrium temperature is 16^(@)C and when 2 litre of water from beaker A then the equilibrium temperature is 14^(@)C .Determine the tempreature of water in the beaker A and B |
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Answer» SOLUTION :Heat lost =Heat gained When 1 litre of water fromA is mixed with2 litres of water FORM B then the EQUILIBRIUM temperature attained is `16^(@)C` `Q=mstraiangelt` Let `t_(A)=2xxsxx(t_(B)-16)` `(16-t_(A))=2(t_(B)-16)` `2t_(B)+t_(A)=18-(1)` When 2 litres of water from A is mixed with 2 liters of water from B then the equilibrium temperture of the mixtrue is `41^(@)C` `2xxSxx(14-t_(A))=2xxSxx(t_(B)-14)` `(14-t_(A))=(t_(B)-14)` `t_(B)+t_(A)=28-(2)` `2t_(B)+2t_(A)=56-(3)` `(3)-(1)rarrt_(A)=8^(@)C` `(t_(B))+(T_(A))=28` `t_(B)=28-t_(A)=28-8-20^(@)C` |
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