Two beakers one containing 20mL of a 0.05M aqueous solution of a nonvolatile, nonelectrolyte and the other, the same volume of 0.03M aqueous solution of NaCl, are placed side by side in a closed encloser. What are the volumes in the two beakers when equilibrium is attained.

Two beakers one containing 20mL of a 0.05M aqueous solution of a nonvo

1.	Two beakers one containing 20mL of a 0.05M aqueous solution of a nonvolatile, nonelectrolyte and the other, the same volume of 0.03M aqueous solution of NaCl, are placed side by side in a closed encloser. What are the volumes in the two beakers when equilibrium is attained.
Answer» Solution :Moles of SOLUTE particles in the first beaker `=(0.05)/(1000)xx20=0.001` Moles of solute particles `(Na^(+)"and"Cl^(-))` in the other beaker `=(2xx0.03)/(1000)xx20=0.0012` As the solution in the first beaker is more dilute than that in the other beaker, the vapour PRESSURE over the solution in the first beaker will be higher than that over the NaCl solution in the SECOND beaker. The water molecules shall thus flow from the first beaker to the other till both the SOLUTIONS have equal MOLARITY. Let this volume of water molecules be vmL. Thus, `(0.001)/(20-v)=(0.0012)/(20+v)` or `v=1.8mL` `:.` volume of the solution in the first beaker `=20-1.8=18.2mL` and the volume of NaCl solution in the other beaker `=20+1.8=21.8mL`