1.

Two beams of light are incident normally on water (mu = 4/3). If one of the beams passes through a glass (mu = 3/2) slab of height 'h' has shown in the figure, the time difference for both the beams for reaching the bottom is (C is velocity of light is vacuum)

Answer»

zero
`(h)/(3C)`
`(6H)/(C )`
`(h)/(6C)`

ANSWER :D


Discussion

No Comment Found

Related InterviewSolutions