Two beams of light having intensities I and 4I interfere to produce a fringe pattern on the screen.Phase differenced between the beamsis (pi)/(2) atpoint A and pi at point B.Then difference between the resultant intensities at A and B is :

Two beams of light having intensities I and 4I interfere to produce a

1.	Two beams of light having intensities I and 4I interfere to produce a fringe pattern on the screen.Phase differenced between the beamsis (pi)/(2) atpoint A and pi at point B.Then difference between the resultant intensities at A and B is :
Answer» 3I 4I 5I 6I Solution :`I_(1) = I , I_(2) = 4I` `theta_(1) = (PI)/(2), theta_(2) = pi` Now, `I_(A) = I_(1) + I_(2) +2sqrt(I_(1)I_(2)) COS (pi)/(2)` ` = I + 4I + 0 = 5I` `I_(B) = I_(1) + I_(2) +2sqrt(I_(1)I_(2)) cos pi = 1` `therefore I_(A) - I_(B) = 5I - I = 4I`

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Two beams of light having intensities I and 4I interfere to produce a fringe pattern on the screen.Phase differenced between the beamsis (pi)/(2) atpoint A and pi at point B.Then difference between the resultant intensities at A and B is :

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