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Two beams of light of intensity I_(1), and I_(2)interfere to give an interference pattern. If the ratio of maximum intensity to that of minimum intensity is (16)/(4) then I_(1):I_(2)= ....... |
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Answer» `1:9` `(16)/(4)=((a_(1)+a_(2))/(a_(1)-a_(2)))^(2)` `=2(a_(1)+a_(2))/(a_(1)-a_(2))^(2)` `2a_(1)-2a_(2)=a_(1)+a_(2)` `:.a_(1)=3a_(2)` `:.(a_(1))/(a_(2))=(3)/(1)` `:.(a_(1)^(2))/(a_(2)^(2))=(9)/(1)` `:.(I_(1))/(I_(2))=(9)/(1) "" [ a_(1)^(2) PROP I_(1),a_(2)^(2) prop I_(2)`Taking K=1 in both] |
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