Two beams P and Q of light of the same wavelength fall upon the same metal surface causing photoemission of electrons. The photoelectric current produced by P is four times that produced by Q. Which of the following gives the ratio ("wave amplitude of beam P")/("wave amplitude of beam Q")?

Two beams P and Q of light of the same wavelength fall upon the same m

1.	Two beams P and Q of light of the same wavelength fall upon the same metal surface causing photoemission of electrons. The photoelectric current produced by P is four times that produced by Q. Which of the following gives the ratio ("wave amplitude of beam P")/("wave amplitude of beam Q")?
Answer» <P>`(1)/(4)` `(1)/(2)` 2 4 Solution :`("WAVE amplitude of beamP")/("Wave amplitude of beam Q")=(("CURRENT of P")^(1//2))/(("Current of Q")^(1//2))=((4)/(1))^((1//2))=2`

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Two beams P and Q of light of the same wavelength fall upon the same metal surface causing photoemission of electrons. The photoelectric current produced by P is four times that produced by Q. Which of the following gives the ratio ("wave amplitude of beam P")/("wave amplitude of beam Q")?

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