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Two beetles run across flat send, starting at the same point. Beetle 1 runs 0.50 m due east, the 0.80 m at 30^(@) north of due east. Beetle 2 also makes two runs, the first is 1.6mat 40^(@) east of due north. What must be (a) the magnitude and (b) the direction of its second run if it is to end up at the new location of beetle 1 ? |
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Answer» Solution :(a) We find `vecD= VECA + vecB-vecC=(0.16m) HATI + (-0.83m) HATJ,and ` the magnituide is `D=0.84m.` (b) The angle is `TAN ^(-1) (-0.83//0.16)=-79^(@)` which is interpreted tomean `79^(@)` south of east (or `11^(@)` east of south). |
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