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Two blocks A and B of same masses are resting in equilibrium on an inclined plane having inclination with horizontal =alpha(gt0). The blocks are touching and exerting no zero normal force on each other with block B higher than A. Coeffcient of static friction of A with incline =1.2 adn of B=0.8. If motons not imminent

Answer»

`alphagt30^(@)`
`("Friction")_(A)gt("Friction")_(B)`
`alphagt45^(@)`
`("Friction")_(A)=("Friction")_(B)`

Solution :`2m sinalpha lt 2mg cos ALPHA`
`f_(A)=mg SIN alpha +N`
`f_(B)=mg sin alpha-N`
To SHOW `N!=0`
`f_(b_("max"))=0.8mgcosalpha`
`=N=mg[sinalpha-0.8cosalpha]`
`N=mg sec alpha [tan alpha-0.8]`
`N=mgsec alpha [tan alpha-0.8]`
For `alpha gt tan^(-1) (0.8)`
`f_(A)gt f_(B)` for `alpha ge tan^(-1)(0.8)f_(A)=f_(B)`


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