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Two blocks m_(1) and m_(2) are placed on a smooth inclined plane as shown in figure. If they are released from rest. Find : (i) acceleration of mass m_(1) and m_(2) (ii) tension in the string (iii) net force on pulley exerted by string. |
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Answer» Solution :F.B.D. of `m_(1)` : `m_(1)gsintheta-T=m_(1)a`  `(sqrt(3))/(2)G-T=sqrt(3)a . . . . . . . . .(i)` F.B.D. of `m_(2)` : `T-m_(2)gsintheta=m_(2)a`  `T-1.(sqrt(3))/(2)g=1.a . . . . . . . . . .(ii)` Adding e.q. (i) and (ii) we GET a=0 Putting this VALUE in eq. (i) we get `T=(sqrt(3)g)/(2)` F.B.D. of pulley `F_(R)=sqrt(2)T` `F_(R)=(sqrt(3))/(2)g` 
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