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Two blocks of masses 10 kg and 4 kg are connected by a negligible mass and placed on a frictionless horizontal surface. An impulse gives a velocity of 14 m/s to the heavier block in the direction of the lighter block. The velocity of the centre of mass is : |
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Answer» 30 m/s `v_(C.M.)=(m_(1)v_(1)+m_(2)v_(2))/(m_(1)+m_(2))=(10xx14+4xx0)/(10+4)=10MS^(-1)` |
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