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Two blocks of masses 5 kg and 2 kg placed on a frictionless surface are connected by a spring. An externalkick gives a velocity of 14 m/s to the heavier block in the direction of the lighter one. Calculate the velocitygained by the centre of mass. |
Answer» <p>momentum of first ball=momentum of second ballm1v1=m2v25*14=2*V2V2=35m/secvelocity of centre of massvcm=m1v1+m2v2/M1+M2=5*14+2*35/75*2+2*510+10=100m/s</p> | |