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Two blocks of masses m and M are connected by means of a metal wire passing over a frictionless fixed pulley. The area of cross-section of the wire is 6.5 xx 10^(-9) m^(2) and its breaking stress is 2 xx 10^(9) Nm^(-2). If m = 1kg, then calculate the maximum value of M (g = 10 m//s^(2)) |
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Answer» Solution :Mg- T = Ma …(i) `T - mg = ma` …(ii) `T = (2Mmg)/((M + m)) RARR (T)/(A) = (2Mmg)/(A(M + m)) = (2MG)/(A (1 + (m)/(M))) = 2 xx 10^(9)` `rArr M = 1.86 kg` 
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