1.

Two blocksof masses 10 kg and 4 kg are connected by a spring of negligible mass and placed on a frictionless horizontal surface. An impulse gives a velocity of 14m/s to the heavier block in the direction of the lighter block. The velocity of the centre of mass is :

Answer»

5 m/s
10 m/s
20 m/s
30 m/s

Solution :Let `V_(C )` be the velocity of CENTRE of mass.
`THEREFORE` By conservation of linear momentum
`MV=(M+m)V_(C)`
`V_(C)=(10xx14)/(10+4)=10ms^(-1)`


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