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Two blocksof masses 10 kg and 4 kg are connected by a spring of negligible mass and placed on a frictionless horizontal surface. An impulse gives a velocity of 14m/s to the heavier block in the direction of the lighter block. The velocity of the centre of mass is : |
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Answer» 5 m/s `THEREFORE` By conservation of linear momentum `MV=(M+m)V_(C)` `V_(C)=(10xx14)/(10+4)=10ms^(-1)` |
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