InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
Two bodies A and B having masses in the ratio of 3 : 1 possess the same kinetic energy. The ratio of their linear momenta is then |
|
Answer» Kinetic energy of body is given by `E_(K)=(1)/(2) mv^(2)` and linear momentum P=mv From Eqs. (i) and (ii), we get `E_(K)=(m^(2)v^(2))/(2m)=(P^(2))/(2m)` When `E_(K_(1)=E_(K_(2)` `implies (P_(1)^(2))/(2m_(1))=(P_(2)^(2))/(2m_(2))" or "(P_(1))/(P_(2))=sqrt((m_(1))/(m_(2)))` or `(P_(1))/(P_(2))=sqrt((3)/(1))` `(P_(2))/(P_(1))=(1)/(sqrt3)` |
|