1.

Two bodies A and B having same surface areas have emmissivities of 0.01 and 0.49 respectively. The two bodies emit total radiant power at the same rate. The wavelength A8 corresponding to maximum spectral radiancy 111 the radiation from B shifted from the wavelength corresponding to maximum spectral radiancy in the radiation from A by 1 µm. Jf temperature of A is 5200 K then,

Answer»

the TEMPERATURE of B is 26006K
the temperature of B is 2000 K and `lamda_B=

Answer :B


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