1.

Two bodies begin a free fall from the same height at a time interval of Ns. If vertical separation between the two bodies is 1 after second from the start of the first body, then is equal to :

Answer»

`sqrt(nN)`
`(1)/(GN)`
`(1)/(gN)+(N)/(2)`
`(1)/(gN)-(N)/(4)`

Solution :Here `S_(1)=(1)/(2)gn^(2)` and `S_2=(G)/(2)(n-N)^(2)`
`S_1-S_2=(1)/(2)g[n^(2)-(n-N)^(2)]`
`1=(g)/(2)(2N-N)(N)`
`2n(2)/(gN)+N` and `n=(1)/(gN)+(N)/(2)`


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