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Two bodies begin to fal from the same height.The second body begins to fall 'tau' s after the first.After what time from the beginning of first body dose the distance between the bodies equals to l? |
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Answer» Solution :Let the time of fall of the 1ST body be t seconds. Time of fall of SECOND body=`t-tau`. Distances of free fall of the bodies in the above time intervals RESPECTIVELY are `H_(1)=("gt"^(2))/(2),H_(2)=(g(t-tau)^(2))/(2)` Therefore `L=H_(1)-H_(2)="gt"tau-(1)/(2)gtau^(2) thereforet=(l)/("gt"au)+(tau)/(2)` |
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