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Two bodies (M) and (N) of equal masses are suspended from two separate massless springs of spring constants (k_1) and (k_2) respectively. If the two bodies oscillate vertically such that their maximum velocities are equal, the ratio of the amplitude of vibration of (M) to the of (N) is.A. `k_1/k_2`B. `k_2/k_1`C. `sqrt(k_1/k_2)`D. `sqrt(k_2/k_1)` |
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Answer» Correct Answer - D `v_(max)=A_Momega_M=A_Nomega_N` `A_M/A_N=omega_N/omega_M=sqrt((k_2lm)/(k_1lm))=sqrt(k_2/k_1)` |
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