InterviewSolution
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InterviewSolution
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Two bodies (M) and (N) of equal masses are suspended from two separate massless springs of spring constants (k_1) and (k_2) respectively. If the two bodies oscillate vertically such that their maximum velocities are equal, the ratio of the amplitude of vibration of (M) to the of (N) is.A. (k_1)/k_2)B. sqrt(k_1)//(k_2)C. (k_2)/(k_1)D. sqrt(k_2)//k_1) |
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Answer» Correct Answer - D Both the bodies oscillate in simple harmonic motion, for the maximum velocities will be Given that `v_1 = v_2 rArr a_1 omega_1 = a_2 omega_2` :. `a_1 xx (2 pi)/(T_1) = a_2 xx (2 pi)/(T_2)` `rArr (a_1)/(a_2) = (T_1)/(T_2) = (2 pi sqrt(m)/(k_1))/(2 pi sqrt(m)/(k_2)) = sqrt(k_2/(k_1))`. |
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