Two bodies of equal masses are heated at a uniform rate under identical conditions. The change in temperature in the two cases in shown graphically. What are their melting points? Find the ratio of their specific heats and latent heats.

Two bodies of equal masses are heated at a uniform rate under identic

1.	Two bodies of equal masses are heated at a uniform rate under identical conditions. The change in temperature in the two cases in shown graphically. What are their melting points? Find the ratio of their specific heats and latent heats.
Answer» The melting points liquids I and II are `60^@` C and `40^@`C, respectively. Let R be the rate of supply of heat. We note from the graph that liquid I is heated through `60^@`C in 2 units of time and that liquid II is heated through `40^@`C in 4 units of time. `2R=mxxc_1xx60` and `4R=mxxc_2xx40` Hence, `(c_1)/(c_2)=(1)/(3)` We note further that the temperature of I remains constant for 4 units of time and that of II for 2 units of time. `4R=mL_1` and `2R=mL_2implies(L_1)/(L_2)=2`

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Two bodies of equal masses are heated at a uniform rate under identical conditions. The change in temperature in the two cases in shown graphically. What are their melting points? Find the ratio of their specific heats and latent heats.

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