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Two bodies of equal masses are some distance apart. If 20 % of mass is transferred from the first body to the second body, then the gravitational force between them |
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Answer» increases by 4% `F_(1)=(Gm^(2))/r^(2)` When 20% MASS is transferred from one BODY to another, then their masses are `m_(1)=80/100mandm_(2)=120/100m` So, force is finally `F_(2)=(Gm^(2))/r^(2)xx(24/25)` Hence, reduction in `F_(2)" is "(F_(1)-F_(2))/F_(1)XX100%=-4%` |
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