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Two bodies of mass `m_(1) and m_(2)` are initially at rest placed infinite distance apart. They are then allowed to move towards each other under mutual gravitational attaction. Show that their relative velocity of approach at separation r betweeen them is `v=sqrt(2G(m_(1)+m_(2)))/(r)`A. `sqrt((2G(m_(1)+m_(2)))/(r)`B. `sqrt((2Gm_(1)m_(2))/((m_(1)+m_(2))r)`C. `sqrt((G(m_(1)+m_(2)))/(r))`D. `sqrt((Gm_(1)m_(2))/((m_(1)+m_(2))r)`

Answer» Correct Answer - A


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