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Two bodies of masses m_1 and m_2 are acted upon by a constant force F for a time t . They start from rest and acquire kinetic energies E_(1) and E_(2) respectively . Then (E_(1))/(E_(2)) is |
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Answer» `(m_1)/(m_2)` `:.V_1=u+a_1t=0+(F)/(m_1).t` `:.E_1=1/2mv_1^2=1/2m_1.(F^2)/(m_1^2).t=(F^2t)/(2m_1)` SIMILARLY`a_2=(F)/(m_2)` `v_2=u+a_2t=0+(F)/(m_2).t` `:.E_2=1/2m_2v_2^2=1/2m_2.(F^2)/(m_2^2)t^2=(F)/(m_1)=(F^2t)/(m_2)` `:.``(E_1)/(E_2)=(m_2)/(m_1)` |
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