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Two bodies of masses m_(1) and m_(2) are attached to the two ends of a string. The passes over a pulley of mass m and radius R. if m_(1)gtm_(2) . The acceleration the system will be |
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Answer» `(m_(1)-m_(2))/(m_(1)+m_(2))G`  `m_(1)g-T_(1)=m_(1)a` `T_(2)-m_(2)g=m_(2)a""....(II)` `:. (T_(1)-T_(2))+(m_(1)+m_(2))a=(m_(1)-m_(2))g` `rArrT_(1)-T_(2)=(m_(1)-m_(2))g-(m_(1)+m_(2))a` `"" tau=(T_(1)-T_(2))R=Ialpha` `"" =(1//2)mR^(2)(a//R)"" ....(iii)` `rArr(T_(1)-T_(2))=(1//2)ma"" ....(IV)` From (iii) and (iv) `"" (1//2)ma=(m_(1)-m_(2))g-(m_(1)+m_(2))a` `rArr a=(m_(1)-m_(2))/(m_(1)+m_(2)+(m//2))g` |
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