Two bodies of masses m and M are placed at distance d apart. The gravitational potential (V) at the position where the gravitational field due to them is zero V isA. `V=-(G)/(d)(m+M)`B. `V=-(G)/(d)`C. `V=-(GM)/(d)`D. `V=-(G)/(d)sqrt(sqrt(m)+sqrt(M))^(2)`

Two bodies of masses m and M are placed at distance d apart. The gravi

1.	Two bodies of masses m and M are placed at distance d apart. The gravitational potential (V) at the position where the gravitational field due to them is zero V isA. `V=-(G)/(d)(m+M)`B. `V=-(G)/(d)`C. `V=-(GM)/(d)`D. `V=-(G)/(d)sqrt(sqrt(m)+sqrt(M))^(2)`
Answer» Correct Answer - D Equilibrium position of the neutral point from mass m is `=((sqrt(m))/(sqrt(m)+sqrt(M)))d` `V_(1)=(-Gm_(1))/(r_(1)),V_(2)=(-Gm_(2))/(r_(2))` `V_(1)=(-Gm)/(sqrt(m)d)(sqrt(M)+sqrt(m)),V_(2)=(-GM)/(sqrt(M)d)(sqrt(M)+sqrt(m))` `V_(1)=(-G)/(d)sqrt(m)(sqrt(M)+sqrt(m)),V_(2)=(-G)/(d)sqrt(M)(sqrt(M)+sqrt(m))` `V=(-G)/(d)(sqrt(M)+sqrt(m))^(2)`

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Two bodies of masses m and M are placed at distance d apart. The gravitational potential (V) at the position where the gravitational field due to them is zero V isA. `V=-(G)/(d)(m+M)`B. `V=-(G)/(d)`C. `V=-(GM)/(d)`D. `V=-(G)/(d)sqrt(sqrt(m)+sqrt(M))^(2)`

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