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Two bodies `P` and `Q` of equal masses are suspended from two separate massless springs of force constants `k_(1)` and `k_(2)` respectively. If the two bodies oscillate vertically such that their maximum velocities are equal. The ratio of the amplitude of `P` to that of `Q` isA. `sqrt((k_(1))/(k_(2))`B. `(k_(1))/(k_(2))`C. `sqrt(k_(2))/(k_(1))`D. `(k_(2))/(k_(1))` |
Answer» Correct Answer - C `omega_(1) A_(1) = omega_(2) A_(2)` `:. (A_(1))/(A_(2)) = (omega_(2))/(omega_(1)) = sqrt(k_(2)//m)/(sqrt(k_(1)//m)) = sqrt(k^(2)/(k_(1)` |
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