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Two bodies start moving in the same straight line at the same instant of time from the same origin. The first body moves with a constant velocity of 40 m/s, and the second starts from rest with a constant acceleration of 4 "m/s"^2. Find the time that elapses before the second catches the first body. Find also the greatest distance between then prior to it and the time at which this occurs. |
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Answer» SOLUTION :When the SECOND body cathces the first ,the distance travelled by eachis the same. `therefore 40t=(1)/(2)(4)t^(2)` or t=20 S Now ,the distance s between the two bodies at any time t is `s=ut-(1)/(2)at^(2)` for s to be maximum, `(ds)/(DT)=0` or u-at =0 or `t=(u)/(a)=(40)/(4)=10S` maximum DIstance `=40xx10-(1)/(2)xx4xx(10)^(2)=400-200=200m` |
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