InterviewSolution
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InterviewSolution
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Two bodiesare projected from the same pointwith equalspeeds in suchdirections thatthey both strikethe same point on a planewhose inclination is beta.If alphathe angleof projectionof the first body with the horizontal , showthat the ratio of theirtime of flights is (sin (alpha - beta))/(cos alpha) |
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Answer» SOLUTION :Let `alpha` be the angle of PROJECTION of the second by . `R =(u^(2))/(G cos^(2) beta) [sin (2alpha - beta)-sin beta]` Range of boththe bodies is sametherefore , `sin(2alpha - beta) = sin (2alpha - beta) or sin 2alpha = pi- (2alpha - beta)` `alpha = (pi)/(2) -(alpha- beta)` Now `T = (2 u sin (alpha - beta))/(g cos beta) and T =(2 usin (alpha - beta))/(g COSE beta)` `therefore (T)/(T) = (2 sin (alpha - beta))/(2 sin (alpha - beta)) = (sin(alpha - beta))/(sin{(pi)/(2) (alpha- beta)-beta})` `sin =((alpha - beta))/(sin((pi)/(2)-alpha)) = (sin(alpha - beta))/(cos alpha)` 
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