1.

Two boys are standing at the ends A and B of a ground where AB = 'a'. The boy at B starts running in a direction perpendicular to AB with a velocity The boy at A also starts running simultaneously with velocity v in straight line and catches the B in time then t is :

Answer»

`a/SQRT(V^(2)+v_(1)^(2))`
`a/(v+v_(1))`
`a/(v-v_(1))`
`sqrt(a^(2)/(v^(2)-v_(1)^(2)))`

Solution :Here as is CLEAR from the fig.
`(v_(1)t)^(2) + a^(2)=(VT)^(2)`or `a^(2)=t^(2)(v^(2)-v_(1)^(2))`
`:.t=sqrt(a^(2)/(v^(2)-v_(1)^(2)))`


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