Two boys are standing at the ends A and B of a ground where AB= a. The boy at B starts running in a direction perpendicular to AB with velocity v. The boy at A starts running simultaneously with velocity v and catches the other in a time t, where t is

Two boys are standing at the ends A and B of a ground where AB= a. The

1.	Two boys are standing at the ends A and B of a ground where AB= a. The boy at B starts running in a direction perpendicular to AB with velocity v. The boy at A starts running simultaneously with velocity v and catches the other in a time t, where t is
Answer» `(a)/(SQRT(NU^(2)+nu_(1)^(2)))` `(a)/(nu+nu_(1))` `(a)/(nu-nu_(1))` `sqrt(a^(2)/(nu^(2)-nu_(1)^(2)))` SOLUTION : `t=(a)/(nu)=(a)/(sqrt(nu^(2)-nu_(1)^(2)))`

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Two boys are standing at the ends A and B of a ground where AB= a. The boy at B starts running in a direction perpendicular to AB with velocity v. The boy at A starts running simultaneously with velocity v and catches the other in a time t, where t is

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