Two Brother X And Y Appeared For An Exam. The Probability Of Selectio

1.	Two Brother X And Y Appeared For An Exam. The Probability Of Selection Of X Is 1/7 And That Of B Is 2/9. Find The Probability That Both Of Them Are Selected?
Answer» LET A be the EVENT that X is selected and B is the event that Y is selected. P(A) = 1/7, P(B) = 2/9. Let C be the event that both are selected. P(C) = P(A) × P(B) as A and B are independent events: = (1/7) × (2/9) = 2/63. Let A be the event that X is selected and B is the event that Y is selected. P(A) = 1/7, P(B) = 2/9. Let C be the event that both are selected. P(C) = P(A) × P(B) as A and B are independent events: = (1/7) × (2/9) = 2/63.

Two Brother X And Y Appeared For An Exam. The Probability Of Selection Of X Is 1/7 And That Of B Is 2/9. Find The Probability That Both Of Them Are Selected?

Answer»

LET A be the EVENT that X is selected and B is the event that Y is selected.

P(A) = 1/7, P(B) = 2/9.

Let C be the event that both are selected.

P(C) = P(A) × P(B) as A and B are independent events:

= (1/7) × (2/9) = 2/63.

Let A be the event that X is selected and B is the event that Y is selected.

P(A) = 1/7, P(B) = 2/9.

Let C be the event that both are selected.

P(C) = P(A) × P(B) as A and B are independent events:

= (1/7) × (2/9) = 2/63.