InterviewSolution
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InterviewSolution
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Two bulbs consume same energy when operated at `200 V and 300 V` , respectively . When these bulbs are connected in series across a dc source of `500 V`, thenA. ratio of potential difference across them is `3//2`B. ratio of potential difference across them is `4//9`C. ratio of power produced in them is `2 // 3`D. ratio of power produced in them is `2//3` |
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Answer» Correct Answer - B `P = (V^(2))/( R) or R = (V^(2))/( p) or R prop V^(2)`, i.e., `(R_(1))/(R_(2)) = ((200)/(300))^(2) = (4)/(9)` when connected in series , potential drops is in the ratio of their resistances . So, `(V_(1))/(V_(2)) = (R_(1))/(R_(2)) = (4)/(9)` Now, `P = I^(2) R` or `P prop R ( "in series I is the same" )` or `(P_(1))/(P_(2)) = (R_(1))/(R_(2)) = ( 4) /( 9)` |
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