A heating coil is rated `100 W , 200 V`. The coil is cut in half and two pieces are joined in parallel to the same source . Now what is the energy `( "in" xx 10^(2) J)` liberated per second?

A heating coil is rated `100 W , 200 V`. The coil is cut in half and t

1.	A heating coil is rated `100 W , 200 V`. The coil is cut in half and two pieces are joined in parallel to the same source . Now what is the energy `( "in" xx 10^(2) J)` liberated per second?
Answer» Correct Answer - 4 Let resistance of heating coil be `R` , then `100 = (200^(2)) /(R ) or R = ((200)^(2))/(100) Omega` Resistance of each cut part is `R//2`. Now , power dissipated is `P = 2(((220)^(2)) / ( R//2))` `= 4 ((220)^(2))/( R ) = 4 xx 100 = 400 W`

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A heating coil is rated `100 W , 200 V`. The coil is cut in half and two pieces are joined in parallel to the same source . Now what is the energy `( "in" xx 10^(2) J)` liberated per second?

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