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    				| 1. | If in the circuit shown in Fig.`7.55`, power dissipation is `150 W` , then find the value of `R ( "in" Omega)`. | 
| Answer» Correct Answer - 6 `150 = (15 xx 15) /( R_(eq)) or R_(eq) = ( 15 xx 15)/( 150) Omega = (3) /(2) Omega` Now, `( 2R)/( 2+ R ) = (3) /( 2) or R = 6 Omega` | |