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Two capacitor of capacity 6 muF and 3muF are charged to 100 V and 50 V separately and connected as shown in figure. Now all the three switches S_1,S_2, and S_3 are closed. Charges on 6muF And 3muF capacitors in steady state will be |
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Answer» `400muC,400muC`  Plates 2 and 3 are joined together and they are neither connected to any of the terminals of the BATTERY nor to any other source of charge. So, they jointly form an isolated system. Before closing the SWITCHES, charge are shown in Fig. After closing the switch let Q charge goes from battery. Then charge on each will increase by q. Applying Kirchhoff's voltage law, we GET `200-((600+q)/(6))-((150+q)/(3))=0` or `q=100muC` so charge on `6muF` capacitor will be `70muC` and `3muF` capacitor will be `250muC` from all the switches `100muC` of charge will flow. |
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