1.

Two capacitors C_(1) and C_(2) arecharged to 120 V and 200 V respectively. It is found that by connecting them together the potential on each one can be made zero. Then

Answer»

`5 C _(1) = 3C_(2)`
`3C_(1)= 5C_(2)`
`3 C_(1) +5C_(2) =0`
`9 C_(1)=4C_(2)`

Solution :Charge on FIRST capacitor
`Q_(1) = C_(1)V_(1)= 120 C_(1)`
Charge on SECOND capacitor,
`Q_(2) = C_(2) V_(2) = 200 C_(2)`
Connecting both of them. If potential on both of them become ZERO then
`Q_(1) = Q_(2)`
`120 C_(1) = 200 C_(2)`
`:. 3 C_(1) = 5 C_(2)`


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