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Two capacitors of a capacitance 3 mu Fand 6mu F respectively are connected in series across a 100 V power supply. Charge on each capacitor is _____________ .

Answer»

Solution :`200 muC`. RESULTANT CAPACITANCE `C_s = (C_1 C_2)/(C_1+C_2) = ((3 xx6))/((3 + 6)) MU F = 2muF `
`:.` CHARGE `Q =C_s. V= 2 MUF xx 100 V= 200 muC`


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