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Two capacitors of capacitance 600 pF and 900 pF are connected in series across a 200 V supply .Calculatethe pd across each capacitor . |
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Answer» Solution :P.d across `C_1` is `V_1=Q/C_1=(720cancel(00)xxcancel(10^(-12)))/(CANCEL(600)xxcancel(10^(-12)))` `V_1=120`V P.d across `C_2` is `V_2=Q/C_2=(720cancel(00)xxcancel(10^(-12)))/(cancel(900)xxcancel(10^(-12)))` `V_2` = 80 V |
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