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Two capacitors of capacitance 600 pF and 900 pF are connected in series across a 200 V supply .Calculate the effective capacitance of the combination. |
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Answer» Solution :Given: `C_1`=600 PF , `C_2` =900 pF V=200V `1/C_S=1/C_1+1/C_2=(C_1+C_2)/(C_1+C_2)` `C_S=(C_1C_2)/(C_1+C_2)=(600xx900)/(600+900)=(54xx10^4)/(15xx10^2)=5400/15`=360 pF
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