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Two capacitors of capacitance C and 3C are charged to potential difference V_(0) and 2V_(0), respectively, and connected to an inductor of inductance L as shows in Fig. Initially, the current in the inductor is zero. Now, switch S is closed. Potential difference across capacitor of capacitance 3C when the current in the circuit is maximum is |
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Answer» `(V_(0))/(4)` `:.` e.m.f. across `L = 0`, so potential difference across the capacitor will be same. From the law of conservation of charge on PLATES `2` and `3`, `3CV + CV = 6 CV_(0) - CV_(0)` `rArr V = (5V_(0))/(4)` Loss in energy of capacitor = energy stored in inductor `rArr (1)/(2) CV_(0)^(2) + (1)/(2) 3C(2V_(0))^(2) - (1)/(2) xx 4CV^(2) = (1)/(2) LI^(2)` `rArr I = (3)/(2) V_(0) sqrt((3C)/(L))`  
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