Saved Bookmarks
| 1. |
Two capacitors of capacitance C and 3C are charged to potential difference V_(0) and 2V_(0), respectively, and connected to an inductor of inductance L as shows in Fig. Initially, the current in the inductor is zero. Now, switch S is closed. The maximum current in the inductor is |
|
Answer» `(3V_(0))/(2) sqrt((3C)/(L))` `:.` e.m.f. across `L = 0`, so potential difference across the capacitor will be same. From the law of CONSERVATION of charge on PLATES `2` and `3`, `3CV + CV = 6 CV_(0) - CV_(0)` `rArr V = (5V_(0))/(4)` LOSS in energy of capacitor = energy stored in inductor `rArr (1)/(2) CV_(0)^(2) + (1)/(2) 3C(2V_(0))^(2) - (1)/(2) XX 4CV^(2) = (1)/(2) LI^(2)` `rArr I = (3)/(2) V_(0) sqrt((3C)/(L))`  
|
|