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Two capacitors of capacitances C_(1) and C_(2) are connected in parallel. If a charge Q is given to the combination, the ratio of the charge on the capacitor C_(1) to the charge on C_(2) will be |
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Answer» `(C_(1))/(C_(2))` [Hint: When two capacitors are connected in parallel, potential DIFFERENCE across them is same i.e., `V_(1)=V_(2)=V`(SAY), So `(Q_(1))/(Q_(2))=(C_(1)V_(1))/(C_(2)V_(2))=(C_(1)V)/(C_(2)V)=(C_(1))/(C_(2)).`] |
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