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Two capacitors of capacities 100muF and 200muF are connected in sereis. A.p.d. of 90 V is applied across them. Calculate the p..d across each capacitor. |
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Answer» Solution :DATA supplied, `C_(1) =100muF","C_(2)=200muF, ""V=90V` Effective capacity `C_(s)=(C_(1)C_(2))/(C_(1)+C_(2))=(100 xx 200)/(300)=(200)/(3) muF` Total charge `Q=C_(s).V=(200)/(3) xx 90=6000muC` Hence p.d. acorss `C_(1)" is "V_(1)=Q/C_(1)=(6000muC)/(100muF)=60"volts"` p.d. across `C_(2)" is "V_(2)=Q/C_(2)=(6000muC)/(200muF)="30 volts"` |
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