1.

Two capacitors of capacity 6 muF and 3 muF are charge 100 V and 50 V separately and connected as shown in Now all the three switches S_(1),S_(2), and S_(3) are closed. Charge on the 3 muF capacitor in steady state willl be.

Answer»

`400 muC`
`700 muC`
`800 muC`
`250 muC`

Solution : (1) `((150-x))/3+((600-x))/6-200=0`
`x=-100 muC`
Hence, final charge on `6 muF` Capacitor is
`q_(1)=700 muC` and charge on `3 muF` is `q_(2)=250 muC`
`q_(1)=(600-x) q_(2)=(150-x)`
. Plates `2` and `3` and plates `1` and `4` form isolated SYSTEM.
Hence `q_(1)=q_(2)=q_(3)=x=-100 muC`.


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