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Two capacitors with capacitances C_(1) and C_(2) are connected in parallel. Find the resultant capacitance. |
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Answer» SOLUTION :When the capacitors are connected in PARALLEL (Fig. 24.9), all their interconnected plates have the same potential, therefore `q_(1)=C_(1)( varphi_(1)-varphi_(2)) and q_(2)=C_(2)(varphi_(1)-varphi_(2))`, where `q_(1) and q_(2)` are thecharges of the RESPECTIVE capacitors. The charge of the system is `q=q_(1)+q_(2)=(C_(1)+C_(2)) (varphi_(1)-varphi_(2))`. On the other h and `q=C(varphi_(1)-varphi_(2))`, where C is the equivalent capacitance. Hence the formula sought. 
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