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Two capacitors with capacitances C_(1) and C_(2) are connected in series. Find the resultant capacitance. |
Answer» SOLUTION :When the capacitors are connected in series (Fig. 24.10), their charges are redistributed so that the charges of all the capacitors are  equal. To make SURE that this is so, consider using Fig. 24.10, what will happen if the system is DISCHARGED by shortcircuiting the POINTS at potentials`varphi_(1) and varphi_(2)`. We have `varphi_(1)-varphi.=q//C_(1), varphi.-varphi_(2)=q//C_(2)` For the system as a whole, Q C g/C. Adding the two former equations and comparing the result with the third, we obtain the formula sought. |
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