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Two cells A and B with same e.m.f of 2 V each and with internal resistances r_(A)=3.5Omega and r_(B)=0.5Omega are connected in series with an external resistance R=3Omega. Find the terminal voltage across the two cells. |
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Answer» Solution :CURRENT through the circuit `i=(epsilon)/((R+r))=(2+2)/((3+3.5+0.5))=(4)/(7)` i) `R=3Omega, r_(A)=3.5Omega, E=2V,` TERMINAL voltage A, `V_(A)=E-ir =2-(4)/(7)xx3.5="0 volt"` ii) `r_(B)=0.5Omega, R=3Omega, E=2V,` Terminal voltage at B, `V_(B)=E-ir=2-(4)/(7)xx0.5="1.714 volts."` |
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