InterviewSolution
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InterviewSolution
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Two cells A and B with same e.m.f. of 2 V each and with internal resistance r_A = 3.5 Omega and r_B = 0.5 Omega are connected in series with an external resistance R = Omega RFind the terminal voltages across the two cells. |
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Answer» Solution :We know `i= V/R =(epsi)/(R+r)` CURRENT through the circuit `i= (epsi)/((R+r)) = (2+2)/((3+3.5 + 0.5))= 4/7` i) `R= 3 Omega , r_A = 3.5 Omega , E= 2V` Terminal voltage across `A, V_A = E - ir_A ` `= 2 - 4/7 xx 3.5 = 0 `volt ii) `r_B = 0.5 Omega, R = 3 Omega , in = 2V` Terminal voltage across B, `V_B = E- ir_B` `= 2- 4/7 xx 0.5 = 1.714 ` volts |
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