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Two cells each emf e but of internal resistance r_1 and r_2 are connected in series through and external resistance R. IF the potential difference across the first cell is zero while current flows the value of R in terms of r_1 and r_2 is |
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Answer» `R=r_1+r_2` `thereforeI=(2E)/(r_1+r_2+R)` Again, POTENTIAL DIFFERENCE =E-1 As the potential across the first cell is zero, when current flows through it `therefore 0=e-(2e)/(r_1+r_2+R)timesr_1thereforeR=r_1-r_2` |
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